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Q.

If α is an  nth root of unity then  1+2α+3α2+....+nαn1=

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a

n1α

b

n(1α)2

c

n1α

d

n(1α)2

answer is C.

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Detailed Solution

S=1+2α+3α2+....+nαn1 αs=α+2α2+....+(n1)αn1+nαn()s(1α)=1+α+α2+....+αn1nαn since  αn=1  S(1α)=0n(1)s=n1α

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