Q.

If  ω is the non-real cube root of unity such that  |(r=1n(r.p=1r(ωp1)))155ω|=(r=1n(r.p=1r(ωp1)))155ω, then n can be equal to 

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a

29

b

32

c

31

d

30

answer is A, B, C.

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Detailed Solution

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r=1n(r.p=1r(ωP1))155ω         =r=1n(r.(ω0+ω1+ω2+....+ωr1))155ω        =1.ω0+2(ω0+ω0)+3(ω0+ω1+ω2)+4(ω0+ω1+ω2+ω3).....       n(ω0+ω1+ω2+.....+ω41)155ω          =1+2(ω2)+3(0)+4(1)+5(ω2)+...

Upto n terms  155ω
Will be real if  n=29,30,31

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If  ω is the non-real cube root of unity such that  |(∑r=1n(r.∑p=1r(ωp−1)))−155ω|=(∑r=1n(r.∑p=1r(ωp−1)))−155ω, then n can be equal to