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If it is known that in Fe_0.96O, Fe is present in +2 and +3 oxidation state. What is the mole fraction of Fe²⁺ in the compound ?

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12/25

25/12

1/12

11/12

answer is D.

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Detailed Solution

Charge balance 2x +3 (0.96 - x)-2 =0,

2x +2.88 - 3x -2 =0

0.88 -x =0

x=0.88

Fraction of Fe⁺² =0.88 and Fe+3 =0.12
% of Fe⁺² = $\frac{0.88}{0.96} \times 100$ =91.6% = $\frac{11}{12}$

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