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If it is known that out of every 5 collisions, 1 has appropriate orientation and activation energy is 4 Kcal then % of effective collisions at 1000 K as per collision theory will be :

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$0.2 e^{- 2}$

$100 e^{- 2}$

$20 e^{- 2}$

answer is D.

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Detailed Solution

Percentage of effective collision,

$% effective = 0.2 \times (e^{\frac{- 4 \times 10^{3}}{2000}}) \times 100 % effective = 20 e^{- 2}$

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