If k > 0 and the product of roots of the equation x² – 3kx + 2e^logk – 1 = 0 is 7, then sum of the roots =

Given equation is $x^2-3kx+2e^{\log k}-1=0$ and $k>0$

Given that the product of the roots of the above equation is 7

The product of the roots of the equation $a{x}^2+bx+c=0$ is  $\frac{c}{a}$

Hence, $2{\mathrm{e}}^{{\log }_{c}k}-1=7\Rightarrow 2k-1=7\Rightarrow 2k=8\Rightarrow k=4$

Sum of the roots of the equation is $-\frac{b}{a}=-\frac{-3k}{1}=3k=\boxed{12}$