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Q.

If  k=119(2)kk!(19k)!=λ19! then  λ  equals.............

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a

3

b

5

c

2

d

1

answer is C.

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Detailed Solution

K=119(2)k19!19!k!(19k)! =119!K=119(2)k.  19Ck   =119![(12)191]=219!

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