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Q.

If k, 2k-1 and 2k+1 are three consecutive terms as an A.P. , then find the value of k.


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a

  k=2

b

  k=3 

c

  k=4

d

  k=5  

answer is B.

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Detailed Solution

Given that k, 2k-1, 2k+1 are three terms in an A.P.
Let a1=k
a2=2k-1
a3=2k+1
We know d=an+1-an Then, the common difference between first two terms,
d = a2- a1
d = 2k-1-
d = k-1 Common difference between next two terms is,
d =a3- a2
d=2k+1-(2k-1) d=2k+1-2k+1
d= 2 The common difference between the 2 consecutive terms should be equal.
Hence,
k-1=2 k=2+1 k=3 Therefore, the value of  k=3 .
Hence, option 2 is correct.
 
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