Q.

If K1 and K2 are the thermal conductivities, L1 and L2 are the lengths and A1 and A2 are the cross sectional areas of steel and copper rods respectively such that K2K1=9, A1A2=2, L1L2=2. Then, for the arrangement as shown in the figure, the value of temperature T of the steel – copper junction in the steady state will be :

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a

14 ºC

b

150 ºC

c

18 ºC

d

45 ºC

answer is C.

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Detailed Solution

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dt=K1A1l1T1T=K2A2l2TT2450TT0=K2A2l1K1A112=9×12×2450T=9TT=45C

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