If k+2,4k−6,3k−2 are the three consecutive terms of an A.P then the value of k is:

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

We are given that the three terms of an A.P as k+2,4k−6,3k−2
Now, let us use the standard condition of an A.P
We know that the condition of an A.P that is a,b,c the three terms of an A.P then
2b=a+c
By using the above condition to given three terms of the A.P we get
⇒2(4k−6)=k+2+3k−2
⇒8k−12=4k
Now, let us interchange the terms in such a way that the variable terms comes one side and constant terms on the other side then we get
⇒8k−4k=12
⇒4k=12
⇒k=3
Therefore we can conclude that the value of k is 3.
So, option (2) is the correct answer.

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE