If kinetic energy of a body is increased by 300% then percentage change in momentum will be :

As $\mathrm{p}=\sqrt{2\mathrm{mK}}$
where P = momentum and K = kinetic energy
$\begin{array}{l}\frac{{\mathrm{p}}_2-{\mathrm{p}}_1}{{\mathrm{p}}_1}\times 100=\frac{\sqrt{2{\mathrm{mK}}_2}-\sqrt{2{\mathrm{mK}}_1}}{\sqrt{2{\mathrm{mK}}_1}}\times 100\\ =\frac{\sqrt{\left({\mathrm{K}}_1+3{\mathrm{K}}_1\right)}-\sqrt{{\mathrm{K}}_1}}{\sqrt{{\mathrm{K}}_1}}\times 100=100\mathrm{\%}\end{array}$