If L=20.04±0.01m and B=2.52±0.02m, what is the value of L×B

L×B=20.04×2.25 ΔL×BL×B%=ΔLL+ΔBB100

If L=20.04±0.01m and B=2.52±0.02m, what is the value of L×B

L×B=20.04×2.25 ΔL×BL×B%=ΔLL+ΔBB100

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If $L = (20.04 \pm 0.01) m$ and $B = (2.52 \pm 0.02) m$ , what is the value of $(L \times B)$

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$50.50 \pm 0.84 %$

$50.50 \pm 0.64 %$

$50.50 \pm 0.42 %$

$50.50 \pm 0.32 %$

answer is C.

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$L \times B = 20.04 \times 2.25 \frac{Δ (L \times B)}{L \times B} % = (\frac{Δ L}{L} + \frac{Δ B}{B}) 100$

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If L=20.04±0.01m and B=2.52±0.02m, what is the value of L×B

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If $L = (20.04 \pm 0.01) m$ and $B = (2.52 \pm 0.02) m$ , what is the value of $(L \times B)$