If L=20.04m±0.01m B=2.52m±0.02m what is the value of (L×B)

L=20.04m±0.0120.04×100%=20.04m±0.05%B=2.52m±0.022.52×100%=2.52m±0.79%L×B=(20.04×2.52)m2±(0.05+0.79)%=50.50m2±0.84%

If L=20.04m±0.01m B=2.52m±0.02m what is the value of (L×B)

L=20.04m±0.0120.04×100%=20.04m±0.05%B=2.52m±0.022.52×100%=2.52m±0.79%L×B=(20.04×2.52)m2±(0.05+0.79)%=50.50m2±0.84%

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If $L = 20.04 m \pm 0.01 m$ $B = 2.52 m \pm 0.02 m$ what is the value of $(L \times B)$

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$50.50 m^{2} \pm 0.84 %$

$50.50 \pm 0.64 %$

$50.50 \pm 0.32 %$

$50.50 \pm 0.42 %$

answer is A.

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Detailed Solution

$L = 20.04 m \pm \frac{0.01}{20.04} \times 100 % = 20.04 m \pm 0.05 %$

$B = 2.52 m \pm \frac{0.02}{2.52} \times 100 % = 2.52 m \pm 0.79 %$

$L \times B = (20.04 \times 2.52) m^{2} \pm (0.05 + 0.79) % = 50.50 m^{2} \pm 0.84 %$

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If L=20.04m±0.01m B=2.52m±0.02m what is the value of (L×B)

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If $L = 20.04 m \pm 0.01 m$ $B = 2.52 m \pm 0.02 m$ what is the value of $(L \times B)$