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If length of a rectangle increased by $50 %$ and breadth decreased by $50 %$ then area will decreased by $\dots \dots$ $%$

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answer is A.

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Detailed Solution

A_{1} = l \times b

$A_{2} = \frac{150}{100} l \times \frac{50}{100} b$

$= \frac{15 \times 5 \times l b}{100}$

$= \frac{3}{4} A_{1}$

$= 75 % A_{1}$

So $A_{2}$ decreased by $25 %$

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