If light of wavelength of maximum intensity emitted from surface at temperature $T_{1}$ is used to cause photoelectric emission from a metallic surface, the maximum kinetic energy of the emitted electron is 6 ev, which is 3 times the work function of the metallic surface. If light of wavelength of maximum intensity emitted from a surface at temperature $T_{2}$ $(T_{2} = 2 T_{1})$ is used, the maximum kinetic energy of the photoelectrons emitted is

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4 eV

2 eV

18 eV

14 eV

answer is C.

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Detailed Solution

from Wien's displacement law if absolute temperature becomes double wavelength becomes halved i.e frequency or energy becomes double

for the first case $h ν = 2 + 6 (a s i t i s g i v e n w o r k f u n c i t o n i s 6 / 3 = 2)$ $\Rightarrow$ $h ν = 8$

for the second case 16 = 2 + K

K= 14

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