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If liquid enters a section of tube of radius $5 c m$ with a velocity $10 m / s$ , with what velocity does the liquid leave another section of the tube of radius $4 c m$ ? The tube is horizontal

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$5.625 m / s$

$15. 625 m / s$

$24 m / s$

$0.625 m / s$

answer is C.

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Detailed Solution

$r_{1}^{2} v_{1} = r_{2}^{2} v_{2}$

$(5 \times 10^{- 2}) \times 10 = {(4 \times 10^{- 2})}^{2} v_{2}$

$v_{2} = \frac{25 \times 10}{16} = 15.625 m / s$

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