If $\log \left(32.5\right)=1.511$  , then the number  of digits in ${\left(325\right)}^{10}$  is

$\log x=10\log 325$

$=10\log \left(32.5\times 10\right)$

$=10\left(\log 32.5+\log 10\right)$

$=10\left(1.511+1\right)$

$=10\left(2.511\right)$

$=25.11$

$\therefore \text{Number of digits}=26$