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Q.

If  (log5x)2+log5x  <2  then  x∈...............

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a

(15,15)

b

(1,∞)

c

(125,5)

d

(5,25)

answer is A.

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Detailed Solution

1
 t2+t−2<0,   t=log5x  
 (t+2)(t−1)=<0   ⇒−2 <t<1
 −2<log5x<1   ⇒ 125<x<5

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