If m > 1, we have (2m)² + (m² – 1)² = (m² + 1)². So, 2m, m² – 1 and m² + 1 forms a [[1]].

If m > 1, we have (2m)² + (m² – 1)² = (m² + 1)². So, 2m, m² – 1, and m² + 1 form a Pythagorean triplet.

For example,

Let us first take m²– 1 = 3

So, m² = 3 + 1 = 4

which gives m = 2

Therefore, 2m = 4 and m² + 1 = 5

The triplet is thus 3, 4, and 5.

This can also be verified as follows:

3² + 4² =5²

9 + 16 = 25

Hence this is verified.