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Q.

If M and N are two natural numbers such that (M = 51) and LCM of M and N is 255, then the HCF of M and N is:


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a

  1

b

  3

c

  5

d

  13 

answer is A.

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Detailed Solution

Concept- To solve this question, we will use the relation that “The product of two numbers will be equal to the product of their LCM and HCF” to get the value of HCF in the form of N as a variable. Then we will find the possible values of N that can give the LCM data provided in the question statement and finally, we will find the HCF in each case using the relation we obtained in the 1st step. Thus, we will obtain our desired answer.
Given, M and N are two natural numbers such that (M = 51) and LCM of M and N is 255, i.e., Question ImageQuestion ImageOn substituting the values, we get,
Question ImageWe can rewrite this equation as,
Question ImageNow we can find all the possible values of Question Image.
For that we can factorise the given LCM and write it as a product of the prime factors.
On factorising, we get
Question ImageOn factorising 51 , we get,
Question ImageSo, we get Question Image as 255 when Question Image is
Question ImageWhen Question Image of Question Image and Question Image is given by Question Image,
Question ImageSo, we have,
Question ImageWhen Question Image of Question Image and Question Image is given by equation Question Image,
Question ImageSo, we have,
Question ImageWhen Question Image of Question Image and Question Image is given by equation(i),
Question ImageSo, we have,
Question ImageWhen Question Image, HCF of Question Image and Question Image is given by equation,
Question ImageSo, we have,
Question ImageSo, the possible values of the Question Image of Question Image and Question Image are 51,3,17 and 1 . Out of these, only 3 and 1 are given in the options.Question ImageHence, the correct answer is option 1) 1 and 2) 3.
 
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