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Q.

If  m is the A.M of the distinct real numbers  l and  n,(ln>1) and  G1,G2,G3 are three G.M’s between  l  and  n  then  G14+2G24+G34=..... 

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a

ln(l+n)2

b

ln(ln)2

c

4lnm2

d

lnm2

answer is A, C.

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Detailed Solution

 2m=l+n l,G1,G2,G3,n  are  in  GP G1l=G2G1=G3G2=nG3 G12=lG2,G22=G1G3,   G32=nG2,G1G3=ln G14+2G24+G34=l2G22+2G24+n2G22 =G22(l2+2ln+n2) =ln(l+n)2 =4lnm2

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