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If molar ratio of CH4(g)  and  He(g) in the shown container is 1 : 3 then the composition (mole ratio of He and  CH4)  of gaseous mixture effusing out initially  when valve is opened, is x : 1. The value of x is
 

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answer is 6.

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Detailed Solution

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nCH4/tnHe/t=PCH4PHeMHeMCH4

=13×416=16

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