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If n = 6, the correct sequence for filling of electrons will be

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$ns \to (n - 1) f \to (n - 2) f \to np$

$ns \to (n - 2) f \to (n - 1) d \to np$

$ns \to np \to (n - 1) d \to (n - 2) f$

$ns \to (n - 2) f \to np \to (n - 1) d$

answer is B.

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Detailed Solution

If the principle quantum number n = 6, the correct sequence of filling of electron will be:
ns→(n−2)f→(n−1)d →np.
Here, n=6. Hence, the correct sequence of filling of electron will be 6s→4f→5d→6p.

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