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If, n, e, $τ$ and m respectively represent the free electron density, charge, relaxation time and mass of the electron, then the resistance of a wire of length l and area of cross – section A will be

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$\frac{ml}{{ne}^{2} τA}$

$\frac{{mτ}^{2} A}{{ne}^{2} l}$

$\frac{{ne}^{2} τA}{2 ml}$

$\frac{{ne}^{2} A}{2 mτl}$

answer is A.

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Detailed Solution

$R = ρ \frac{l}{A} = \frac{m}{{ne}^{2} τ} \cdot \frac{l}{A}$

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