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Q.

If n is a positive integer, then value of (3n+2)nC0+(3n-1)nC1+(3n-4)nC2+....+_2(nCn)  is

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a

(3n+4)2n-1

b

(3n)2n

c

(3n-1)2n

d

(3n-3)2n

answer is A.

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Detailed Solution

Let S=(3n+2)nC0+(3n-1)nC1+.+2 nCn    1 

S=2 nC0+5 nC1++(3n-1)nCn-1+(3n+2)nCn   2(1)+(2)2 S=(3n+4)C0   n+C1   n++Cn-1   n+Cn   n=(3n+4)2nS=(3n+4)2n-1

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