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Q.

If n is a positive integer, then value of (3n+2)nC0+(3n1)nC1+(3n4)nC2++2 nCn is

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a

(3n+4)2n1

b

(3n)2n

c

(3n1)2n

d

(3n3)2n

answer is A.

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Detailed Solution

Let S=(3n+2)nC0+(3n1)nC1++5nCn1+2nCn(1)

     S=2nCn+5nCn1++(3n1)nC1+(3n+2)nC0S=2nC0+5nC1++(3n1)nCn1+(3n+2)nCn(2)(1)+(2)2S=(3n+4) nC0+nC1++nCn1+nCn=3n+42nS=3n+42n-1

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