Q.

If n is even and  nC0<nC1<nC2<<nCr>nCr+1>nCr+2>..>nCn, then,  r=

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a

n2

b

n12

c

n22

d

n+22

answer is A.

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Detailed Solution

From the given relation it is evident that  nCr  is the

greatest ;1mong the values  nCn,nC1,,nCr 

We know that  nCr is greatest for r=n2. Hence r=n2.

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If n is even and  nC0<nC1<nC2<…<nCr>nCr+1>nCr+2>…..>nCn, then,  r=