If n is even and the middle term in the expansion of (x2+1x)n is 924x6 . Then n is

Since, n is even, these for (n2+1)th term is the middle term ∴Tn2+1=nCn2(x2)n2(1x)n2=924x6⇒xn2=x6 ∴n=12

If n is even and the middle term in the expansion of (x2+1x)n is 924x6 . Then n is

Since, n is even, these for (n2+1)th term is the middle term ∴Tn2+1=nCn2(x2)n2(1x)n2=924x6⇒xn2=x6 ∴n=12

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If n is even and the middle term in the expansion of ${(x^{2} + \frac{1}{x})}^{n}$ is $924 x^{6}$ . Then n is

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Since, n is even, these for ${(\frac{n}{2} + 1)}^{t h}$ term is the middle term
$∴ T_{\frac{n}{2} + 1} = n_{C_{\frac{n}{2}}} {(x^{2})}^{\frac{n}{2}} {(\frac{1}{x})}^{\frac{n}{2}} = 924 x^{6}$

$\Rightarrow x^{\frac{n}{2}} = x^{6}$    $∴ n = 12$

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If n is even and the middle term in the expansion of ${(x^{2} + \frac{1}{x})}^{n}$ is $924 x^{6}$ . Then n is