If n is odd natural number, then coefficient of xn in e5x+exe3x is

e5x+exe3x =e2x+e-2x =21+(2x)22+(2x)44+...If n is odd natural number then xn coef=0

If n is odd natural number, then coefficient of xn in e5x+exe3x is

e5x+exe3x =e2x+e-2x =21+(2x)22+(2x)44+...If n is odd natural number then xn coef=0

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If n is odd natural number, then coefficient of xⁿ in $\frac{e^{5 x} + e^{x}}{e^{3 x}}$ is

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$\frac{2^{n}}{2!}$

$\frac{2}{n}$

$\frac{n}{2}$

answer is D.

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$\begin{array}{rcl} \frac{e^{5 x} + e^{x}}{e^{3 x}} \\ = & e^{2 x} + e^{- 2 x} \\ = & 2 [1 + \frac{{(2 x)}^{2}}{2} + \frac{{(2 x)}^{4}}{4} + . . .] \end{array}$

If n is odd natural number then

$x^{n} coef = 0$

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If n is odd natural number, then coefficient of xn in e5x+exe3x is

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If n is odd natural number, then coefficient of xⁿ in $\frac{e^{5 x} + e^{x}}{e^{3 x}}$ is