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Q.

If $N_{0}$ is the original mass of the substance of half-life period $T_{1 / 2} = 5 years$ , then the amount of substance left after 15 years is

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a

$\frac{N_{0}}{8}$

b

$\frac{N_{0}}{16}$

c

$\frac{N_{0}}{2}$

d

$\frac{N_{0}}{4}$

answer is A.

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Detailed Solution

$N = N_{0} {(\frac{1}{2})}^{\frac{t}{T_{1 / 2}}} = N_{0} {(\frac{1}{2})}^{\frac{15}{5}} = \frac{N_{0}}{8}$

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If N0 is the original mass of the substance of half-life period T1/2= 5 years, then the amount of substance left after 15 years is