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Q.

If n1, n2 and n3 are the fundamental frequencies of three elements into which a string is divided, then the original fundamental frequency n of the string is given by

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a

1n=1n1+1n2+1n3

b

1n=1n1+1n2+1n3

c

n=n1+n2+n3

d

n=n1+n2+n3

answer is A.

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Detailed Solution

detailed_solution_thumbnail

Total length of string,  l=l1+l2+l3
(As string is divided into three segments)
But frequency 1length(f=12lTm)
So, 1n=1n1+1n2+1n3

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