Q.

If n1,n2,n3........  are the frequencies of segments of a stretched string the frequency n of the string is given by ..

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a

n=n1+n2+n3+........

b

n=n1×n2×n3×.....

c

n=n12+n22+n32+.....

d

1n=1n1+1n2+1n3+...

answer is C.

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Detailed Solution

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For a vibrating string
n1l1=n2l2=n3l3......=constant=k(say)=nl
Also  l1+l2+l3+l4+.......=1

kn1+kn2+kn3+kn4+......=kn1n=1n1+1n2+1n3+...
 
 

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