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If $N_{A}, N_{B} and N_{C}$ are the number of significant figures in A= 0.001204 m, B =43120000 m and C = 1.200 m respectively then

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$N_{A} = N_{B} = N_{C}$

$N_{A} > N_{B} > N_{C}$

$N_{A} < N_{B} < N_{C}$

$N_{A} > N_{B} < N_{C}$

answer is A.

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Detailed Solution

$N_{A} = 4, N_{B} = 4, N_{C} = 4$

So $N_{A} = N_{B} = N_{C}$

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