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Q.

If nN  and A=(a000b000c)  then An=

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a

0

b

1

c

(00an0bn0cn00)

d

(an000bn000cn)

answer is B.

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Detailed Solution

A=(a000b000c)

A2=(a000b000c)×[a000b000c]=[a2000b2000c2]

A3=[a2000b2000c2]×[a000b000c]=[a3000b3000b3]

An=(an000bn000cn)

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