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If nPr1a=nPrb=nPr+1c , then which of the following holds good

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By Expert Faculty of Sri Chaitanya
a
c2=a(b+c)
b
a2=c(a+b)
c
b2=a(b+c)
d
1a+1b+1c=1
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detailed solution

Correct option is C

Given, nPr1a=nPrb=nPr+1c

n!a(nr+1)!=n!b(nr)!=n!c(nr1)!

1a(nr+1)(nr)(nr1)!=1b(nr)(nr1)!=1c(nr1)!

1a(nr+1)(nr)=1b(nr)=1c


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