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If number of molecules of H₂ are double than that of O₂, then ratio of kinetic energy of Hydrogen molecule to that of Oxygen molecule at 300 K is

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1:1

1:2

2:1

1:16

answer is A.

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Detailed Solution

At temperature T, kinetic energy of each molecule =

where f = number of degrees of freedom.

For O₂ and H₂ , f = 5

\therefore \frac{{{{\left( {KE} \right)}_{{H_2}}}}}{{{{\left( {KE} \right)}_{{O_2}}}}}\, = \,\frac{{\frac{{5{K_B}T}}{2}}}{{\frac{{5{K_B}T}}{2}}}\, = \,1

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