If OA is equally inclined to OX, OY and OZ and if A is $\sqrt{3}$ units from the origin then A is

$$\begin{gathered} \mathrm{If} \mathrm{OA}=\sqrt{3} \mathrm{and} \angle \mathrm{AOX}=\angle \mathrm{AOY}=\angle \mathrm{AOZ} \\ {\cos }^2\alpha +{\cos }^2\beta +{\cos }^2\gamma =1 \\ given that \alpha =\beta =\gamma \\ \Rightarrow \cos \alpha =\cos \beta =\cos \gamma =\frac{1}{\sqrt{3}} \\ \mathrm{A}\text{ is }(\mathrm{OAcos}\alpha ,\mathrm{OAcos}\beta ,\mathrm{OAcos}\gamma )=(1,1,1) \end{gathered}$$