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If one end of a diameter of the ellipse 4x² + y² = 16 is ( , $\sqrt{3}$ , 2), then the other end is:

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$(- \sqrt{3}, 2)$

$(\sqrt{3}, - 2)$

$(- \sqrt{3}, - 2)$

(0,0)

answer is C.

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Detailed Solution

Since every diameter of an ellipse passes through the centre and is bisected by it, therefore the coordinates of the other end are $(- \sqrt{3}, - 2)$

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