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If one mole of a gas A (mol.wt-40) occupies a volume of 20litres, under the same conditions of temperature and pressure the volume occupied by 2 moles of gas B (mol.wt=80) is

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80 L

60 L

50 L

40 L

answer is D.

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Detailed Solution

$V_{1} n_{2} = V_{2} n_{1} 20 \times 2 = V_{2} X 1 T h u s, V_{2} = 40 L$

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