If one mole of AgCl is dopped with 10-5 mole of 2 CaCl2 , the number of Ag+ ions lost from the lattice

1 mole of Ca+2 → 2x6x1023 Ag+ lost10-5 mole Ca+2 →=1.2x1019

If one mole of AgCl is dopped with 10-5 mole of 2 CaCl2 , the number of Ag+ ions lost from the lattice

1 mole of Ca+2 → 2x6x1023 Ag+ lost10-5 mole Ca+2 →=1.2x1019

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If one mole of AgCl is dopped with 10^-5mole of 2 CaCl₂ , the number of Ag⁺ ions lost from the lattice

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10^-5

6x10⁸

1.2x10¹⁹

3x10¹⁸

answer is C.

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Detailed Solution

1 mole of Ca⁺² → 2x6x10²³ Ag⁺ lost
10^-5 mole Ca⁺² →
=1.2x10¹⁹

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If one mole of AgCl is dopped with 10-5 mole of 2 CaCl2 , the number of Ag+ ions lost from the lattice

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If one mole of AgCl is dopped with 10^-5mole of 2 CaCl₂ , the number of Ag⁺ ions lost from the lattice