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If one number of a Pythagorean triplet is 2m, then the other two numbers are

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𝑚, 𝑚²+ 1

𝑚² + 1, 𝑚² − 1

𝑚, 𝑚² − 1

𝑚², 𝑚² + 1

answer is B.

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Detailed Solution

m² + 1, 𝑚² − 1, 2𝑚 then the smallest number is 2m
Greatest number is 𝑚² + 1

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