If one of the diameters of the circle x2 + y2 - 2x - 6y + 6 =0 is a chord to the circle with center (2, 1), then the radius of the circle is

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If one of the diameters of the circle x² + y² - 2x - 6y + 6 =0 is a chord to the circle with center (2, 1), then the radius of the circle is

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answer is 3.

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The given circle is x² + y²-2x - 6y + 6 - 0
Its center is H(1, 3) and radius ts 2.
AH=2

Radius of the required circle = AC

$= \sqrt{{AH}^{2} + {CH}^{2}} = \sqrt{2^{2} + 5} = 3$

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