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Q.

If one of the roots of 18x3+81x2+121x+60=0 is equal to half the sum of the other two then one of its roots is

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a

23

b

32

c

32

d

23

answer is A.

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Detailed Solution

α,β,γ  are roots

α=12(γ+β)2α=β+γ

α+β+γ=8118

αβ+βγ+γα=12118

αβγ=6018

α+2α=8118

3α=8118

α=32

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