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Q.

If one of the roots of 18x3+81x2+121x+60=0 is equal to half the sum of the other two then one of its roots is

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a

23

b

−32

c

32

d

−23

answer is A.

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Detailed Solution

α,β,γ  are roots

α=12(γ+β)⇒2α=β+γ

α+β+γ=−8118

αβ+βγ+γα=12118

αβγ=−6018

α+2α=−8118

3α=−8118

α=−32

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