Q.

If one root of a quadratic equation (2 + √3), then form the equation given that the roots are irrational.

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a

x2 - x + 4 = 0

b

x2 - 4x + 1 = 0

c

4x2 - 4x + 1 = 0

d

4x2 - 5x + 6 = 0

answer is A.

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Detailed Solution

As (2 + √3) is an irrational number.

We already know the fact that irrational roots of a quadratic equation will occur in conjugate pairs.

That is,  if (2 + √3) is one root of a quadratic equation, then (2 - √3) will be the other root of the same equation.

So, (2 + √3) and (2 - √3) are the roots of the required quadratic equation.

The Sum of the roots is = (2 + √3) + (2 - √3) = 4

The product of the roots is = (2 + √3)(2 - √3)

                                            = 22 - √32 = 4 - 3 = 1

Then the quadratic equation : 

=> x2 - (sum of the roots)x + product of the roots = 0

=> x2 - 4x + 1 = 0

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If one root of a quadratic equation (2 + √3), then form the equation given that the roots are irrational.