If one root of the equation (a2−5a+3)x2+(3a−1)x+2=0 is twice as large as the other then the value of 1a is------(Where[.] represents greatest integer function)

Let roots be p,2p 3p=−(3a−1)a2−5a+3⇒2p2=2(a2−5a+3)⇒(3a−1)29(a2−5a+3)=1⇒39q=2b,a=2/3

If one root of the equation (a2−5a+3)x2+(3a−1)x+2=0 is twice as large as the other then the value of 1a is------(Where[.] represents greatest integer function)

Let roots be p,2p 3p=−(3a−1)a2−5a+3⇒2p2=2(a2−5a+3)⇒(3a−1)29(a2−5a+3)=1⇒39q=2b,a=2/3

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If one root of the equation $(a^{2} - 5 a + 3) x^{2} + (3 a - 1) x + 2 = 0$ is twice as large as the other then the value of $[\frac{1}{a}]$ is------
(Where[.] represents greatest integer function)

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$\begin{array}{l} L e t r o o t s b e p, 2 p 3 p = \frac{- (3 a - 1)}{a^{2} - 5 a + 3} \\ \Rightarrow 2 p^{2} = \frac{2}{(a^{2} - 5 a + 3)} \Rightarrow \frac{{(3 a - 1)}^{2}}{9 (a^{2} - 5 a + 3)} = 1 \\ \Rightarrow 39 q = 2 b, a = 2 / 3 \end{array}$

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If one root of the equation (a2−5a+3)x2+(3a−1)x+2=0 is twice as large as the other then the value of 1a is------(Where[.] represents greatest integer function)

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If one root of the equation $(a^{2} - 5 a + 3) x^{2} + (3 a - 1) x + 2 = 0$ is twice as large as the other then the value of $[\frac{1}{a}]$ is------
(Where[.] represents greatest integer function)