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Q.

If one root of the equation x2+(13i)x2(1+i)=0 is -1 + i, then the other root is

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a

-1-  i

b

1i2

c

i

d

2i

answer is D.

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Detailed Solution

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Let another root of equation
x2+(13i)x2(1+i)=0  is αα+(1+i)=(13i)α=2i

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