If P(A)=13 , P(B)=12 and P(A∪B)=56 then events A and B are

PA+PB=13+12=56PA∪B=PA+PB⇒PA∩B=0

If P(A)=13 , P(B)=12 and P(A∪B)=56 then events A and B are

PA+PB=13+12=56PA∪B=PA+PB⇒PA∩B=0

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If $P (A) = \frac{1}{3}$ , $P (B) = \frac{1}{2}$ and $P (A \cup B) = \frac{5}{6}$ then events A and B are

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$P (A) + P (B) = \frac{1}{3} + \frac{1}{2} = \frac{5}{6}$

$P (A \cup B) = P (A) + P (B) \Rightarrow P (A \cap B) = 0$

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If P(A)=13 , P(B)=12 and P(A∪B)=56 then events A and B are

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If $P (A) = \frac{1}{3}$ , $P (B) = \frac{1}{2}$ and $P (A \cup B) = \frac{5}{6}$ then events A and B are