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Q.

If P and Q are the lengths of the perpendiculars from the origin to the lines  x cos θ + y sin θ = k cos 2 θ and x sec θ  y cosec θ = k respectively then

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a

p2-4q2=k2

b

p2+4q2=k2

c

4p2+4q2=k2

d

p2+q=k2

answer is B.

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Detailed Solution

p=|kcos2θ|cos2θ+sin2θ=|kcos2θ|q=|k|sec2θ+coses2θ=|ksinθcosθ|  =|k(1/2)sin2θ|
So p2+4q2=k2cos22θ+sin22θ=k2.

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