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If P, Q are the points of trisection of A (1, - 2), B (- 5, 6) then PQ =

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10/3

5/2

answer is C.

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Detailed Solution

$I f P a n d Q a r e p o i n t s o f t r i s e c t i o n o f A B t h e n PQ = \frac{1}{3} AB = \frac{1}{3} \sqrt{(1 + 5)^{2} + (- 2 - 6)^{2}} = \frac{1}{3} \sqrt{36 + 64} = \frac{10}{3}$

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