If P8 15=A+8P7 14then A=

Formula:npr+r.npr−1=n+1pr A+8.14p7=15p8=14P8+8.14p7⇒A=14p8

If P8 15=A+8P7 14then A=

Formula:npr+r.npr−1=n+1pr A+8.14p7=15p8=14P8+8.14p7⇒A=14p8

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If ${}^{15}P_{8} = A + 8 {}^{14}P_{7}$ then A=

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${}^{14}P_{6}$

${}^{14}P_{8}$

${}^{15}P_{7}$

${}^{16}P_{9}$

answer is B.

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$F o r m u l a : n_{p_{r}} + r . n_{p_{r - 1}} = n + 1_{p_{r}}$

$A + {8.14}_{p_{7}} = 15_{p_{8}} = 14_{P_{8}} + {8.14}_{p_{7}} \Rightarrow A = 14_{p_{8}}$

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If P8 15=A+8P7 14then A=

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If ${}^{15}P_{8} = A + 8 {}^{14}P_{7}$ then A=