If PA¯= 0.7, P (B) = 0.7 and P (B I A) = 0.5, then P (A I B) =

P(A∩B)=P(A)P(B∣A)=0.3×0.5=0.15P(A∣B)=P(A∩B)P(B)=0.150.7=1570=314

If PA¯= 0.7, P (B) = 0.7 and P (B I A) = 0.5, then P (A I B) =

P(A∩B)=P(A)P(B∣A)=0.3×0.5=0.15P(A∣B)=P(A∩B)P(B)=0.150.7=1570=314

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If $P (\bar{A})$ = 0.7, P (B) = 0.7 and P (B I A) = 0.5, then P (A I B) =

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$3 / 2$

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Detailed Solution

$P (A \cap B) = P (A) P (B ∣ A) = 0.3 \times 0.5 = 0.15$

$P (A ∣ B) = \frac{P (A \cap B)}{P (B)} = \frac{0.15}{0.7} = \frac{15}{70} = \frac{3}{14}$

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If PA¯= 0.7, P (B) = 0.7 and P (B I A) = 0.5, then P (A I B) =

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If $P (\bar{A})$ = 0.7, P (B) = 0.7 and P (B I A) = 0.5, then P (A I B) =